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Showing posts with label Intergers. Show all posts
Showing posts with label Intergers. Show all posts

Wednesday, December 12, 2012

Jessica Da Silva's Scribepost

Textbook pages 290-292

4) Jasmine said that she did not need any integer chips to multiply 0 x (+2) or to multiply (-3) x 0. Explain her thinking.

Answer: Jasmine did not need to add any integer chips because there is nothing to multiply it by. Multiplying zero is the same thing as multiply nothing so the answer is zero.

5) Write each repeated addition as a multiplication.

a) (+1) + (+1) + (+1) + (+1) + (+1)
Answer: (+5) x (+1) = (+5)

b) (-6) + (-6)
Answer: (+2) x (-6) = (-12)

9) What multiplication statement does each set of diagrams represent?

a)





 
 
 
 
 
 
Answer: (+2) x (-4)
 
b) 





 
 
 
 
 


Answer: (+4) x (-2)

18) Does doubling an integer always result in an integer of greater value? Explain.
Answer: No, because when you double a negative integer, the answer or result will be a lesser value.

Here is a video to help you with multiplying integers if you are still having difficulties.




Here is a link as well for those of you who still don't get how to multiply integers.

Tuesday, December 11, 2012

Ryan's Scribepost

Well today in class we learn how to multiply postive integer and negative integers.

First we do Multiply the factors than ask remove groups of so you are left with (+)
or Multiply the factors than ask groups of (-) so you are with (+) also. ( I think)

Lets do 3 x 5. This is the easy one because it is (+3) x (+5) so you just multiply the two numbers together and the answer would be (+15). You can solve this by words using "groups of are" The number before groups is the first number and the one after of is the 2nd number and after are is the answer by solving it but you only do this if your answer is over 20. If it is under 20 you use the intergers tiltes (donut holes or timbits.)

First you draw 5 groups of 3 than. Than you add them up.
My next question is (-6) x  2 = (-12) istead of doing groups first you do this. "Removing 6 groups of 2 are (-12) You would solve this by using pictures. Like this.
 
The blue is negative and the red is postive. You would do 6 groups of 2 first than do the zero pair below it. Than you add it all again.
My last question is 7 x (-3) to solve this question you would do the 7 groups of (-3) and than do zero pair and if you can't see the question it is +21.
 
Hope you understand how to multiply integers. 
 


Sunday, December 2, 2012

Edens interger scribepost



 Intergers in Standard Form

Owe 3  Owe 1  Owe 4
1. (-3) + (-1) = (-4)

To write intergers in standard form, first you have to remove the brackets ( )

-3      -1


Thats how you write intergers in standard form.



How to solve problem:

Interger chips
Number line.
Owe and have


More Standard Form.... :)


(+3) + (+3)=                   (-8) +  (-3)
  
 3         3                         -8        -3        


I couldn't find a good video, so here's a website that will help :

http://www.mathgoodies.com/lessons/vol5/intro_integers.html



                                 I hope I explained it enough :)


                                         Have a good night